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  1. For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/phRead more

    For an ideal inductor connected across a sinusoidal A.C. voltage source, the average power over the full cycle is zero. This is because the voltage and current are out of phase by π/2, resulting in no net energy transfer.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/

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  2. (i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor. (ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/

    (i) The reactive element causing the current to lag the voltage by a phase angle of π/2 is an inductor.
    (ii) The reactive element causing the current to lead the voltage by π/2 is a capacitor.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/

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  3. Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitatioRead more

    Given the mass of the sphere M = 100 kg, the mass of the particle m = 10 g or 10⁻² kg, and the radius R = 10 cm or 0.01 m, the initial potential energy (P.E.) of the two bodies is calculated based on their gravitational interaction. When the particle is moved far away from the sphere, the gravitational potential energy of the system becomes zero. The work done in moving the particle from its initial position to an infinite distance is the difference between the final and initial potential energies, resulting in a positive value.

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  4. Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms For Vrms = 200V and I rms = 10 A, the power dissipation is P = 1/2 × 200 × 10 = 1000 W. For more visit here: https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapterRead more

    Since the current and voltage are in phase, the power factor cosϕ = 1. The power dissipation is given by P = V rms I rms
    For Vrms = 200V and I rms = 10 A,
    the power dissipation is P = 1/2 × 200 × 10 = 1000 W.

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    https://www.tiwariacademy.com/ncert-solutions/class-12/physics/chapter-7/

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  5. In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy rRead more

    In the given scenario, the initial potential energy of the system is determined by the gravitational interaction between the two masses. When the particle is moved infinitely far away, the potential energy becomes zero. To move the particle from its initial position to infinity, the kinetic energy required is equivalent to the change in potential energy. This kinetic energy can be understood as the work needed to overcome the gravitational attraction between the two bodies. The amount of kinetic energy required is proportional to the gravitational acceleration, the mass of the particle, and the radius of the sphere.

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