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The eccentricity of a hyperbola is
Choice (d) is correct. As eccentricity of a hyperbola is greater than unity. This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11Read more
Choice (d) is correct.
As eccentricity of a hyperbola is greater than unity.
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
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If e is eccentricity of the ellipse x² /a² + y² /b² = 1 (where a > b) then
Choice (b) is correct. This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
Choice (b) is correct.
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
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If the line 5x – 4y = a passes through the focus of the parabola y² = 20x, the value of a is
Choice (c) is correct. The given parabola is y² = 20x, which is of the form y² = 4ax. a = 5 and focus of the given parabola is (a , 0) i.e., (5, 0). It is given that the line 5x - 4y = a passes through the focus (5, 0). 5(5) - 4(0) = a ⇒ a = 25 This question related to Chapter 10 maths Class 11th NCRead more
Choice (c) is correct.
The given parabola is y² = 20x, which is of the form y² = 4ax.
a = 5 and focus of the given parabola is (a , 0) i.e., (5, 0).
It is given that the line 5x – 4y = a passes through the focus (5, 0).
5(5) – 4(0) = a ⇒ a = 25
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The length of the latus rectum of the ellipse x² /12 + y² /4 = 1 is
Choice (d) is correct. The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1 ⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x - ( -3)}² = 10 Thus, the centre of the circle is (-3, -1). This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answerRead more
Choice (d) is correct.
The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1
⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x – ( -3)}² = 10
Thus, the centre of the circle is (-3, -1).
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The center of the circle (x + 3)² + (y + 1)² – 25 = 0 lies on the line
Choice (a) is correct. The given circle is (x + 3)² + (y + 1)² - 25 = 0 ⇒ [x - (-3)]² + [ y - (-1)]² =(5)² ⇒ (-3, -1) is the centre of the circle. On checking whether (-3, -1) lies on options (a) or (b) or (c) or (d), we find that it lies on 5x + y + 16 = 0 5 (-3) + (-1) + 16 = 0 which is true. ThiRead more
Choice (a) is correct.
The given circle is (x + 3)² + (y + 1)² – 25 = 0
⇒ [x – (-3)]² + [ y – (-1)]² =(5)²
⇒ (-3, -1) is the centre of the circle.
On checking whether (-3, -1) lies on options (a) or (b) or (c) or (d), we find that it lies on 5x + y + 16 = 0
5 (-3) + (-1) + 16 = 0 which is true.
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10