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Describe the process and benefits of Full Yogic Breathing (Purna Svasa).
Full Yogic Breathing (Pūrna Śvāsa) combines abdominal, thoracic, and clavicular breathing, maximizing lung expansion and oxygen intake. Inhale deeply, filling the abdomen, chest, and collarbones sequentially, then exhale fully. This practice strengthens the respiratory system, improves lung capacityRead more
Full Yogic Breathing (Pūrna Śvāsa) combines abdominal, thoracic, and clavicular breathing, maximizing lung expansion and oxygen intake. Inhale deeply, filling the abdomen, chest, and collarbones sequentially, then exhale fully. This practice strengthens the respiratory system, improves lung capacity, and reduces stress by calming the nervous system. Pūrna Śvāsa enhances mental clarity, promotes emotional stability, and energizes the body, making it a cornerstone of holistic Yoga practice for physical and mental well-being.
See lessA particle covers 20m in the first 2 seconds of its motion from rest under uniform acceleration. What is the magnitude of its acceleration?
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s: 20 = 0 +1/2a(2²) 20 = 2a a = 10 m/s². For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The second equation of motion is s = ut +1/2at². Substituting u = 0, s = 20m and t = 2s:
20 = 0 +1/2a(2²)
20 = 2a
a = 10 m/s².
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A particle undergoes uniform circular motion. About which point on the plane of the circle, will the angular momentum of the particle remain conserved?
In uniform circular motion, the particle moves along a circular path at constant speed. For such a particle, angular momentum is conserved about any point in the plane of the circle if no external torques act on the system; thus, the angular momentum is constant about any point in the plane of the cRead more
In uniform circular motion, the particle moves along a circular path at constant speed. For such a particle, angular momentum is conserved about any point in the plane of the circle if no external torques act on the system; thus, the angular momentum is constant about any point in the plane of the circle.
The conservation of angular momentum is one of the principles in physics. According to it, if there is no external torque acting on the system, its angular momentum will be conserved. For a uniform circular motion, the motion of the particle is restricted to a plane and the forces that act upon it are internal to the system. Thus, its angular momentum will be conserved about any point within that plane.
It should be noted that even though the angular momentum is conserved about points that are inside the plane of the circle, the value of the angular momentum is dependent on the selection of the reference point. On the other hand, the reason that it remains conserved about any point in the plane results directly from the lack of external torques.
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See lessA car starts from rest and accelerates uniformly at 5m/s². What will be its velocity after 4 seconds?
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values: v = 0 + 5 × 4 = 20 m/s. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
The first equation of motion is v = u + at. Here, u = 0, a = 5m/s² and t = 4s. Substituting these values:
v = 0 + 5 × 4 = 20 m/s.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-2/
A particle is confined to rotate in a circular path with decreasing liner speed. Then which of the following is correct?
When a particle moves in a circular path with decreasing linear speed, it experiences a tangential acceleration directed opposite to its velocity, causing it to slow down. This deceleration results in a reduction of the particle's angular momentum over time. Thus, the angular momentum of the particlRead more
When a particle moves in a circular path with decreasing linear speed, it experiences a tangential acceleration directed opposite to its velocity, causing it to slow down. This deceleration results in a reduction of the particle’s angular momentum over time. Thus, the angular momentum of the particle is not conserved in this scenario.
If the speed of the particle were constant, then it would only have centripetal acceleration toward the center of the circle, so it would have a constant angular momentum. In this case, the existence of tangential acceleration means that the speed of the particle, and hence its angular momentum, will change.
Therefore, the correct statement is that the angular momentum of the particle is not conserved while it moves in a circular path with decreasing linear speed.
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