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What does the angular momentum of a system depend on?
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: httpRead more
Angular momentum 𝐿 = 𝐼 𝜔, so it depends directly on the moment of inertia 𝐼 and angular velocity ω. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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A spring 40 mm long is stretched by the application of a force. If 10 N force is required to stretch the spring through 1 mm, then work done in stretching the spring through 40 mm is
To solve the problem of calculating work done in stretching a spring, we must refer to the property of the spring as described in Hooke's Law. In this law, it is defined that the amount of force applied to stretch the spring is proportional to the stretching from its original length. The force increRead more
To solve the problem of calculating work done in stretching a spring, we must refer to the property of the spring as described in Hooke’s Law. In this law, it is defined that the amount of force applied to stretch the spring is proportional to the stretching from its original length. The force increases linearly with the degree of stretching the spring. The work done in stretching the spring is equivalent to the energy stored in it, often referred to as elastic potential energy.
The work done is visualized to be the area under a graph of force extension. Since this relationship between the force and extension is linear, the graph plots as a triangle. The extension of the spring is represented by the base of this triangle, while the height would represent the maximum force required. Therefore, work done is directly proportional to the square of extension.
In this given case, the spring would need a force of 10 N for every millimeter of extension, and it is stretched 40 mm. When we use the formula for work done in a spring, substituting the given values enables us to calculate how much energy is in the spring due to this extension. When using the result of this computation, we obtain a total work done of 8 J, meaning it amounts to the amount of energy required to extend the spring by 40 mm.
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If the angular velocity of a wheel is halved, how does its rotational kinetic energy change?
Rotational kinetic energy is 𝐾𝐸 = 1/2𝐼𝜔². If 𝜔 is halved, 𝜔² becomes 1/4. Thus, the energy is reduced to one-fourth. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more pleaseRead more
Rotational kinetic energy is 𝐾𝐸 = 1/2𝐼𝜔². If 𝜔 is halved, 𝜔² becomes 1/4. Thus, the energy is reduced to one-fourth. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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What is the moment of inertia of a hollow sphere of mass 𝑀 and radius 𝑅 about an axis passing through its center?
The moment of inertia of a hollow sphere about its diameter is derived as I = 2/3MR². This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: https://www.tiwariRead more
The moment of inertia of a hollow sphere about its diameter is derived as I = 2/3MR². This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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A bomb of mass 3.0 kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg. The smaller mass goes at a speed of 89 ms⁻¹ . The total energy imparted to the two fragments is
A 3.0 kg bomb explodes in mid-air, breaking into two pieces of mass 2.0 kg and 1.0 kg. The smaller piece, with mass 1.0 kg, is ejected at a speed of 89 m/s. We want to find the total energy transferred to the two pieces. First, we will calculate the kinetic energy of the smaller piece. The kinetic eRead more
A 3.0 kg bomb explodes in mid-air, breaking into two pieces of mass 2.0 kg and 1.0 kg. The smaller piece, with mass 1.0 kg, is ejected at a speed of 89 m/s. We want to find the total energy transferred to the two pieces. First, we will calculate the kinetic energy of the smaller piece. The kinetic energy depends on the mass and the square of the speed of the fragment. We apply the principle of conservation of momentum to find the speed of the larger fragment. Since the total momentum before the explosion is zero, the momentum after the explosion must also equal zero. So, by studying the masses and velocities, we can deduce the speed of the 2.0 kg fragment.
After calculating the kinetic energy of each fragment, these values are combined to find total energy imparted during the explosion. The calculated total energy expresses the amount of energy released from the explosion, which is equally distributed between two fragments. Hence, the answer shows the quantity of energy transmitted to the fragments, which remains a significant requirement in the domain of physics as an understanding related to the mechanics of explosions.
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