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What is the moment of inertia of a thin ring of mass 𝑀 and radius 𝑅 about an axis passing through its center and perpendicular to its plane?
The moment of inertia of a thin ring about an axis passing through its center and perpendicular to its plane is given by 𝐼 = 𝑀𝑅² since all the mass is distributed at a distance 𝑅 from the axis. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and RoRead more
The moment of inertia of a thin ring about an axis passing through its center and perpendicular to its plane is given by 𝐼 = 𝑀𝑅² since all the mass is distributed at a distance 𝑅 from the axis.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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A rigid body is in rotational equilibrium if:
Both net force and net torque acting on the body are zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutionsRead more
Both net force and net torque acting on the body are zero. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/
What is the angular velocity of a body rotating at 360° per second in radians per second?
To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding. For moreRead more
To convert degrees to radians, multiply by 𝜋/180. Here, 360° × 𝜋/180 = 2𝜋 radians. Hence, the angular velocity is 2𝜋 rad/s. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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What is the moment of inertia of a solid sphere of mass 𝑀 and radius 𝑅 about an axis passing through its diameter?
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere's uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and RotationalRead more
The formula for the moment of inertia of a solid sphere about an axis through its diameter is 𝐼 = 2/5 𝑀𝑅². This is derived based on the sphere’s uniform mass distribution and symmetry. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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What is the position of the center of mass of a uniform rod of length 𝐿 and mass 𝑀?
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod. This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give anRead more
For a uniform rod, the mass distribution is symmetric, so the center of mass lies at the geometrical center. Therefore, the center of mass is at the midpoint of the rod.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-6/