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  1. The acceleration due to gravity on Earth's surface is approximately: g₀ = 9.8 m/s² This value represents the gravitational force experienced by an object per unit mass at the Earth's surface. It is derived from the formula: g₀ = G * M / R² Where: g₀ = acceleration due to gravity on Earth's surface GRead more

    The acceleration due to gravity on Earth’s surface is approximately:

    g₀ = 9.8 m/s²

    This value represents the gravitational force experienced by an object per unit mass at the Earth’s surface. It is derived from the formula:

    g₀ = G * M / R²

    Where:
    g₀ = acceleration due to gravity on Earth’s surface
    G = gravitational constant (approximately 6.674 × 10^-11 N m²/kg²)
    M = mass of the Earth (approximately 5.972 × 10^24 kg)
    R = radius of the Earth (approximately 6,371 km or 6.371 × 10^6 m)

    Substituting these values results in the standard value of g₀ ≈ 9.8 m/s².

    This value can vary slightly depending on altitude, latitude, and local geological structures.
    This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/

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  2. The gravitational force between the Earth and the Sun is primarily determined by: 1. **Mass of the Sun (Mₛ):** The Sun's mass is a key factor in the gravitational force. The larger the mass of the Sun, the stronger the gravitational pull it exerts on the Earth. 2. **Mass of the Earth (Mₑ):** The EarRead more

    The gravitational force between the Earth and the Sun is primarily determined by:

    1. **Mass of the Sun (Mₛ):**
    The Sun’s mass is a key factor in the gravitational force. The larger the mass of the Sun, the stronger the gravitational pull it exerts on the Earth.

    2. **Mass of the Earth (Mₑ):**
    The Earth’s mass also contributes to the gravitational force. The force is proportional to the product of the two masses (Mₛ * Mₑ).

    3. **Distance between Earth and Sun (r):**
    The distance between the Earth and the Sun plays a critical role in determining the gravitational force. According to the inverse square law, the gravitational force decreases with the square of the distance (1/r²).

    The gravitational force is mathematically given by:

    F = G * (Mₛ * Mₑ) / r²

    Where:
    F = gravitational force
    G = gravitational constant (approximately 6.674 × 10^-11 N m²/kg²)
    Mₛ = mass of the Sun (approximately 1.989 × 10^30 kg)
    Mₑ = mass of the Earth (approximately 5.972 × 10^24 kg)
    r = average distance between Earth and Sun (approximately 1.496 × 10^11 m)

    Key Point:
    The two most significant factors in determining the gravitational force are the masses of the Earth and the Sun, and the distance between them.
    This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/

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  3. In the case where a shell in flight breaks into four unequal parts, we consider the conservation laws that apply: 1. Momentum: The momentum of the system is conserved in the absence of external forces. Before the explosion, the shell has a certain momentum, and after the explosion, the total momentuRead more

    In the case where a shell in flight breaks into four unequal parts, we consider the conservation laws that apply:

    1. Momentum: The momentum of the system is conserved in the absence of external forces. Before the explosion, the shell has a certain momentum, and after the explosion, the total momentum of all the parts will equal the initial momentum of the shell.

    2. Kinetic Energy: Kinetic energy is not necessarily conserved in explosions or inelastic collisions. When the shell explodes, some of the energy is transformed into other forms (like sound, heat, etc.), so the total kinetic energy after the explosion will not equal the kinetic energy before the explosion.

    3. Potential Energy: In this situation, neither potential energy is preserved, particularly when the explosion causes a change in the height of the parts.

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    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-5/

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  4. Inside a uniform spherical shell, gravitational field is zero due to symmetry and the shell theorem. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncRead more

    Inside a uniform spherical shell, gravitational field is zero due to symmetry and the shell theorem. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/

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  5. According to the equivalence principle, gravitational and inertial mass are equivalent, making their effects indistinguishable. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding. For more please visit here: httpsRead more

    According to the equivalence principle, gravitational and inertial mass are equivalent, making their effects indistinguishable. This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-7/

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