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  1. In formula format: ΔL = (F × L) / (A × Y) Where: - F= applied load which is the same for both the wires - L= length of wire which is the same for both - A= cross sectional area of the wire A = πd² / 4 - Y = Young's modulus (same material, so constant for both wires) The extension is **inversely propRead more

    In formula format:
    ΔL = (F × L) / (A × Y)

    Where:
    – F= applied load which is the same for both the wires
    – L= length of wire which is the same for both
    – A= cross sectional area of the wire A = πd² / 4
    – Y = Young’s modulus (same material, so constant for both wires)

    The extension is **inversely proportional to the cross-sectional area (A)

    Step 1: Calculate the area ratio
    For the first wire (diameter = d):
    A₁ = (π × d²) / 4

    For the second wire (diameter = 2d):
    A₂ = (π × (2d)²) / 4 = (π × 4d²) / 4 = πd²

    Area ratio is:
    A₁ : A₂ = (πd² / 4) : πd² = 1 : 4

    Step 2: Ratio of extensions
    Since extension (ΔL) is inversely proportional to the area:
    ΔL₁ : ΔL₂ = A₂ : A₁ = 4 : 1

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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  2. Bhrāmarī Prānāyāma, or the "bee breath," involves a gentle humming sound during exhalation. It calms the nervous system, reduces anxiety, and relaxes the mind. This practice fosters mindfulness, improves concentration, and balances emotions. Regularly practicing Bhrāmarī alleviates stress, enhancesRead more

    Bhrāmarī Prānāyāma, or the “bee breath,” involves a gentle humming sound during exhalation. It calms the nervous system, reduces anxiety, and relaxes the mind. This practice fosters mindfulness, improves concentration, and balances emotions. Regularly practicing Bhrāmarī alleviates stress, enhances mental clarity, and promotes a state of calm. It is especially beneficial for individuals seeking to reduce mental fatigue and improve their emotional and mental well-being.

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  3. Performing Prānāyāma under a teacher ensures correct technique, which is essential for effective results and avoiding harm. A teacher can guide breathing practices, correct mistakes, and address individual challenges. Proper guidance helps practitioners maintain safety, achieve intended benefits, anRead more

    Performing Prānāyāma under a teacher ensures correct technique, which is essential for effective results and avoiding harm. A teacher can guide breathing practices, correct mistakes, and address individual challenges. Proper guidance helps practitioners maintain safety, achieve intended benefits, and progress steadily. Teachers also provide personalized instructions and ensure alignment with traditional practices, creating a supportive environment for holistic growth and mastery of Prānāyāma techniques.

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  4. Stress is defined as the internal restoring force per unit area developed in a material when it is deformed due to an external force. It is expressed as 𝜎 = 𝐹/𝐴. This question related to Chapter 8 physics Class 11th NCERT. From the Chapter 8. Mechanical Properties of Solids. Give answer according toRead more

    Stress is defined as the internal restoring force per unit area developed in a material when it is deformed due to an external force. It is expressed as 𝜎 = 𝐹/𝐴. This question related to Chapter 8 physics Class 11th NCERT. From the Chapter 8. Mechanical Properties of Solids. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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  5. The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula: A = (π × d²) / 4 Step 1: Determine the areas First wire (diameter = 1 mm): A₁ = (π × 1²) / 4 = π / 4 Second wire (diameter = 2 mm): A₂ = (π × 2²) / 4 = 4π / 4 = π The area of the seconRead more

    The breaking tension of a wire is proportional to its cross-sectional area. It can be determined using the formula:

    A = (π × d²) / 4

    Step 1: Determine the areas
    First wire (diameter = 1 mm):
    A₁ = (π × 1²) / 4 = π / 4

    Second wire (diameter = 2 mm):
    A₂ = (π × 2²) / 4 = 4π / 4 = π
    The area of the second wire is **4 times** the area of the first wire.

    Step 2: Calculate the breaking tension
    Breaking tension is proportional to the area.

    For the first wire:
    T₁ = 1000 N

    For the second wire:
    T₂ = 4 × T₁ = 4 × 1000 = 4000 N

    Click here for more:
    https://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/

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