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What is Prānāyāma and how is it defined in Yoga?
Prānāyāma, derived from Yoga, is the practice of controlling and expanding the life force (Prāna) through regulated breathing. The word combines "Prāna" (life force) and "Ayāma" (control/expansion). This practice enhances energy flow, calms the mind, improves concentration, and promotes harmony. RegRead more
Prānāyāma, derived from Yoga, is the practice of controlling and expanding the life force (Prāna) through regulated breathing. The word combines “Prāna” (life force) and “Ayāma” (control/expansion). This practice enhances energy flow, calms the mind, improves concentration, and promotes harmony. Regular practice supports a healthy respiratory system and strengthens the connection between the body and mind, fostering overall physical and mental balance.
See lessWhat are the three important practices in Prānāyāma? Briefly describe each.
The three essential practices in Prānāyāma are: Puraka (Inhalation): A deep, controlled intake of breath to nourish the body. Rechaka (Exhalation): Slow, complete release of breath to expel toxins. Kumbhaka (Retention): Temporarily holding the breath, enhancing focus and energy flow. These practicesRead more
The three essential practices in Prānāyāma are:
See lessPuraka (Inhalation): A deep, controlled intake of breath to nourish the body.
Rechaka (Exhalation): Slow, complete release of breath to expel toxins.
Kumbhaka (Retention): Temporarily holding the breath, enhancing focus and energy flow.
These practices collectively balance the breathing rhythm, improve lung capacity, and enhance physical and mental health.
A wire whose cross-sectional area is 2 mm² is stretched by 0.1 mm by a certain load, and if a similar wire of triple the area of cross-section is stretched by the same load, then the elongation of the second wire would be
The formula for the elongation of a wire is as follows: ΔL = (F L) / (A Y) Where: ΔL is the elongation, F is the force, L is the original length of the wire, A is the cross-sectional area, Y is Young's Modulus. For the first wire, the elongation is given by: ΔL1 = (F L) / (A1 Y) For the second wire,Read more
The formula for the elongation of a wire is as follows:
ΔL = (F L) / (A Y)
Where:
ΔL is the elongation,
F is the force,
L is the original length of the wire,
A is the cross-sectional area,
Y is Young’s Modulus.
For the first wire, the elongation is given by:
ΔL1 = (F L) / (A1 Y)
For the second wire, the elongation is given by:
ΔL2 = (F L) / (A2 Y)
Since the area of the second wire is three times that of the first wire, A2 = 3 A1, we can compare the elongations:
ΔL2 / ΔL1 = A1 / A2 = 1 / 3
Thus, the elongation of the second wire is one-third that of the first wire:
ΔL2 = ΔL1 / 3 = 0.1 mm / 3 = 0.033 mm
The correct answer is:
0.033 mm
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/
Why should practitioners avoid forcing deep breathing during Āsanas?
Deep or forced breathing during Āsanas may create unnecessary tension, reducing the pose's effectiveness and increasing the risk of discomfort or strain. Breathing naturally through the nose supports the body's rhythm, ensures oxygen flow, and maintains relaxation. This mindful approach fosters a haRead more
Deep or forced breathing during Āsanas may create unnecessary tension, reducing the pose’s effectiveness and increasing the risk of discomfort or strain. Breathing naturally through the nose supports the body’s rhythm, ensures oxygen flow, and maintains relaxation. This mindful approach fosters a harmonious balance between movement and breath, enhancing the physical and mental benefits of the practice.
See lessA sphere of radius 3 cm is subjected to a pressure of 100 atm. Its volume decreases by 0.3 c.c. What will be its bulk modulus?
We can use the formula to find the bulk modulus as follows: Bulk Modulus (B) = (Pressure × ΔV) / V Where: - Pressure P = 100 atm - Change in volume ΔV = 0.3 c.c. - Initial volume V of the sphere is given by the formula for the volume of a sphere: V = (4/3) π r³ For r = 3 cm: V = (4/3) π (3)³ = 36 πRead more
We can use the formula to find the bulk modulus as follows:
Bulk Modulus (B) = (Pressure × ΔV) / V
Where:
– Pressure P = 100 atm
– Change in volume ΔV = 0.3 c.c.
– Initial volume V of the sphere is given by the formula for the volume of a sphere:
V = (4/3) π r³
For r = 3 cm:
V = (4/3) π (3)³ = 36 π c.c.
Now, let’s calculate the bulk modulus:
B = (100 atm × 0.3 c.c.) / (36 π c.c.)
Simplifying the above expression gives us the answer
B = 4 π × 10⁵ atm
Thus the correct answer is
4π x 10⁵ atm
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/physics/chapter-8/