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The property to flow is unique to fluids. Which one of the following statements is correct? (a) Only gases behave like fluids. (b) Gases and solids behave like fluids. (c) Gases and liquids behave like fluids. (d) Only liquids are fluids.
(c) Gases and liquids behave like fluids. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(c) Gases and liquids behave like fluids.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See lessThe latent heat of fusion of ice in J/kg is (a) 3.34 x 10⁵ (b) 33.4 x 10⁵ (c) 30.4 x 10⁵ (d) 3.04 x 10⁵
(a) This is the correct answer. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(a) This is the correct answer.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See lessDuring summer, water kept in an earthen pot becomes cool because of the phenomenon of (a) diffusion. (b) transpiration. (c) osmosis. (d) evaporation.
(d) Evaporation causes cooling and the water becomes cool. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(d) Evaporation causes cooling and the water becomes cool.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
See lessThe area bounded by the curve y log x, x-axis, ordinates x = 1 and x = 2 in sq. units is
The area bounded by the curve y = log x, the x-axis, and the ordinates x = 1 and x = 2 can be found using the definite integral of log x from x = 1 to x = 2. Step 1: Write the integral The area is calculated as: A = ∫₁² log x dx Step 2: Integrate This can be evaluated as a result of integration by pRead more
The area bounded by the curve y = log x, the x-axis, and the ordinates x = 1 and x = 2 can be found using the definite integral of log x from x = 1 to x = 2.
Step 1: Write the integral
The area is calculated as:
A = ∫₁² log x dx
Step 2: Integrate
This can be evaluated as a result of integration by parts. Note that the integration by parts formula is as follows:
∫ u dv = uv – ∫ v du
Here let u = log x and dv = dx, then du = (1/x) dx, v = x
Thus
∫ log x dx = x log x – ∫ x (1/x) dx = x log x – x
Step 3: Calculate the result
Now integrate the integral from x = 1 to x = 2:
A = [x log x – x]₁²
When x = 2,
2 log 2 – 2
When x = 1,
1 log 1 – 1 = 0 – 1 = -1
Hence area is:
A = (2 log 2 – 2) – (-1) = 2 log 2 – 2 + 1 = 2 log 2 – 1
Now substituting the value for log 2 = 0.693.
A ≈ 2(0.693) – 1 = 1.386 – 1 = 0.386
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-8
Which of the following sublimes on heating? (a) Iodine (b) Camphor (c) Naphthalene (d) All of these.
(d) All the substances mentioned show the property of sublimation. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
(d) All the substances mentioned show the property of sublimation.
https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/
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