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  1. The area bounded by the curve y = log x, the x-axis, and the ordinates x = 1 and x = 2 can be found using the definite integral of log x from x = 1 to x = 2. Step 1: Write the integral The area is calculated as: A = ∫₁² log x dx Step 2: Integrate This can be evaluated as a result of integration by pRead more

    The area bounded by the curve y = log x, the x-axis, and the ordinates x = 1 and x = 2 can be found using the definite integral of log x from x = 1 to x = 2.

    Step 1: Write the integral
    The area is calculated as:

    A = ∫₁² log x dx

    Step 2: Integrate
    This can be evaluated as a result of integration by parts. Note that the integration by parts formula is as follows:
    ∫ u dv = uv – ∫ v du
    Here let u = log x and dv = dx, then du = (1/x) dx, v = x
    Thus
    ∫ log x dx = x log x – ∫ x (1/x) dx = x log x – x
    Step 3: Calculate the result
    Now integrate the integral from x = 1 to x = 2:

    A = [x log x – x]₁²

    When x = 2,

    2 log 2 – 2

    When x = 1,

    1 log 1 – 1 = 0 – 1 = -1

    Hence area is:

    A = (2 log 2 – 2) – (-1) = 2 log 2 – 2 + 1 = 2 log 2 – 1

    Now substituting the value for log 2 = 0.693.

    A ≈ 2(0.693) – 1 = 1.386 – 1 = 0.386

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    https://www.tiwariacademy.com/ncert-solutions/class-12/maths/#chapter-8

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  2. (d) All the substances mentioned show the property of sublimation. https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/

    (d) All the substances mentioned show the property of sublimation.

    https://www.tiwariacademy.com/ncert-solutions/class-9/science/chapter-1/

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