Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
We want to connect the people who have knowledge to the people who need it, to bring together people with different perspectives so they can understand each other better, and to empower everyone to share their knowledge.
The length of the latus rectum of the ellipse x² /12 + y² /4 = 1 is
Choice (d) is correct. The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1 ⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x - ( -3)}² = 10 Thus, the centre of the circle is (-3, -1). This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answerRead more
Choice (d) is correct.
The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1
⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x – ( -3)}² = 10
Thus, the centre of the circle is (-3, -1).
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The center of the circle (x + 3)² + (y + 1)² – 25 = 0 lies on the line
Choice (a) is correct. The given circle is (x + 3)² + (y + 1)² - 25 = 0 ⇒ [x - (-3)]² + [ y - (-1)]² =(5)² ⇒ (-3, -1) is the centre of the circle. On checking whether (-3, -1) lies on options (a) or (b) or (c) or (d), we find that it lies on 5x + y + 16 = 0 5 (-3) + (-1) + 16 = 0 which is true. ThiRead more
Choice (a) is correct.
The given circle is (x + 3)² + (y + 1)² – 25 = 0
⇒ [x – (-3)]² + [ y – (-1)]² =(5)²
⇒ (-3, -1) is the centre of the circle.
On checking whether (-3, -1) lies on options (a) or (b) or (c) or (d), we find that it lies on 5x + y + 16 = 0
5 (-3) + (-1) + 16 = 0 which is true.
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The length of semi – latus rectum of the parabola x² = 20y is
Choice (c) is correct. The equation of the parabola is x² = 20y which is of the form x² = 4ay where 4a = 20. Length of semi-latus rectum = 2a = 10. This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding. For more plRead more
Choice (c) is correct.
The equation of the parabola is x² = 20y
which is of the form x² = 4ay where 4a = 20.
Length of semi-latus rectum = 2a = 10.
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The equation of the circle which touches the x- axis and whose centre is (3, 4) is
Choice (a) is correct. As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x - 3)² + (y - 4)² = 4² This question related to Chapter 10 maths Class 11th NCERT.Read more
Choice (a) is correct.
As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x – 3)² + (y – 4)² = 4²
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The equation of the directrix of the parabola y² = -8x is
Choice (a) is correct. As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x - 3)² + (y - 4)² = 4² This question related to Chapter 10 maths Class 11th NCERT.Read more
Choice (a) is correct.
As the coordinates of the centre are (3, 4) and radius = 4 because distance of a point (on x-axis) on a circle from the centre (3, 4) is the y-coordinates i.e., 4 so, the required equation is (x – 3)² + (y – 4)² = 4²
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10