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The centre of the circle x² + y² + 6x + 2y = 0 is
Choice (d) is correct. The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1 ⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x - ( -3)}² = 10 Thus, the centre of the circle is (-3, -1). This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answerRead more
Choice (d) is correct.
The given circle is x² + y² + 6x + 2y = 0 ⇒ x² + 6x + 9 + y² + 2y + 1 = 9 + 1
⇒ (x + 3)² + (y + 1)² = 10 ⇒ {x – ( -3)}² = 10
Thus, the centre of the circle is (-3, -1).
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
If the line ax + by + c = 0 is a diameter of the circle x² + y² = 4, then the value of c is
Choice (a) is correct. Given circle is x² + y² = 4 ⇒ (x - 0)² + (y - 0)² = 2² ⇒ (0 - 0) is centre and 2 units is the radius of the given circle. Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it ⇒ a.0 + b.0 + c = 0 ⇒ 0 + 0 + c =0 ⇒ c =0 This question related to Chapter 10 maRead more
Choice (a) is correct.
Given circle is x² + y² = 4
⇒ (x – 0)² + (y – 0)² = 2²
⇒ (0 – 0) is centre and 2 units is the radius of the given circle.
Now, since ax + by + c = 0 is a diameter therefore (0, 0) must lie on it
⇒ a.0 + b.0 + c = 0
⇒ 0 + 0 + c =0
⇒ c =0
This question related to Chapter 10 maths Class 11th NCERT. From the Chapter 10: Conic Section. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-10
The equation of the straight line which passes through the point (1, 2) and cuts off equal intercepts from the axes is
Choice (b) is correct. Let the intercepts on the axes be a and a respectively. The equation of the line is x/a + y/a = 1 ⇒ x + y = a Since the line passes through the point (1, 2), their coordinates must satisfy the equation (1). 1 + 2 = a ⇒ a = 3 Putting the value of a in (1), the equation of theRead more
Choice (b) is correct.
Let the intercepts on the axes be a and a respectively.
The equation of the line is x/a + y/a = 1 ⇒ x + y = a
Since the line passes through the point (1, 2), their coordinates must satisfy the equation (1).
1 + 2 = a ⇒ a = 3
Putting the value of a in (1), the equation of the line is x + y = 3.
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
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The slope of the straight line 2x – 7y = 13 is
Choice (d) is correct. The line is 2x - 7y = 13 Slope of the line, m = - coefficient of x / coefficient of y = -(2/-7) = 2/7 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: httpsRead more
Choice (d) is correct.
The line is 2x – 7y = 13
Slope of the line, m = – coefficient of x / coefficient of y = -(2/-7) = 2/7
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
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See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9
The slope of the straight line, whose inclination with x-axis is 60° is
Choice (a) is correct. Here, θ = 60° Slope of the line = m = tan 60° = √3 This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding. For more please visit here: https://www.tiwariacademy.com/ncert-solutions/class-11/maRead more
Choice (a) is correct.
Here, θ = 60°
Slope of the line = m = tan 60° = √3
This question related to Chapter 9 maths Class 11th NCERT. From the Chapter 9: Straight Lines. Give answer according to your understanding.
For more please visit here:
See lesshttps://www.tiwariacademy.com/ncert-solutions/class-11/maths/#chapter-9