What's your question?
  1. Illustrate a character who transitions between professions through outfit changes. As a doctor, they appear serious and confident; as an athlete, they show determination and energy; as an artist, they look imaginative and expressive. The comic highlights how attire affects perception and self-expresRead more

    Illustrate a character who transitions between professions through outfit changes. As a doctor, they appear serious and confident; as an athlete, they show determination and energy; as an artist, they look imaginative and expressive. The comic highlights how attire affects perception and self-expression. Changing roles influences posture, emotions and societal expectations, demonstrating that clothing plays a crucial role in shaping how individuals present themselves.

    See less
    • 25
  2. Given: - Height of original cone = H = 30 cm, - Volume of smaller cone = (1/27) × Volume of original cone. For similar cones: (h/H)³ = 1/27 ⇒ h/H = 1/3. Height of smaller cone: h = (1/3) × 30 = 10 cm. Height above the base: H - h = 30 - 10 = 20 cm. Final Answer: c) 20 cm. This question related to ChRead more

    Given:
    – Height of original cone = H = 30 cm,
    – Volume of smaller cone = (1/27) × Volume of original cone.

    For similar cones:
    (h/H)³ = 1/27 ⇒ h/H = 1/3.

    Height of smaller cone:
    h = (1/3) × 30 = 10 cm.

    Height above the base:
    H – h = 30 – 10 = 20 cm.

    Final Answer: c) 20 cm.
    This question related to Chapter 12 Mathematics Class 10th NCERT. From the Chapter 12. Surface Areas and Volumes. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

    See less
    • 31
  3. Given: - Total volume of solid = 3 × Volume of cone, - Height of cone = h. Volumes - Volume of cone = (1/3)πr²h, - Volume of cylinder = πr²H (H = height of cylinder), - Total volume = Volume of cone + Volume of cylinder. Equation for total volume Total volume = 3 × Volume of cone: (1/3)πr²h + πr²H =Read more

    Given:
    – Total volume of solid = 3 × Volume of cone,
    – Height of cone = h.

    Volumes
    – Volume of cone = (1/3)πr²h,
    – Volume of cylinder = πr²H (H = height of cylinder),
    – Total volume = Volume of cone + Volume of cylinder.

    Equation for total volume
    Total volume = 3 × Volume of cone:
    (1/3)πr²h + πr²H = 3 × (1/3)πr²h.

    Simplify:
    πr²H = (3/3)πr²h – (1/3)πr²h,
    πr²H = (2/3)πr²h.

    Cancel πr²:
    H = (2/3)h.
    This question related to Chapter 12 Mathematics Class 10th NCERT. From the Chapter 12. Surface Areas and Volumes. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

    See less
    • 30
  4. Given: - Cone is cut at the midpoint of its height. Smaller cone dimensions - Height and radius of smaller cone are half of the original cone. Volume ratio - Volume of smaller cone = (1/8) × Volume of original cone. Final Answer: d) 1:8. For more please visit here: https://www.tiwariacademy.in/ncertRead more

    Given:
    – Cone is cut at the midpoint of its height.

    Smaller cone dimensions
    – Height and radius of smaller cone are half of the original cone.

    Volume ratio
    – Volume of smaller cone = (1/8) × Volume of original cone.

    Final Answer: d) 1:8.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

    See less
    • 25
  5. The sphere's volume is 288π cm³. When submerged, it displaces an equal volume of water in the cylinder. Using the formula for the cylinder's volume, πr²h = 288π, and substituting r = 8 cm, we get: 64πh = 288π → h = 288 / 64 = 4.5 cm. This question related to Chapter 12 Mathematics Class 10th NCERT.Read more

    The sphere’s volume is 288π cm³. When submerged, it displaces an equal volume of water in the cylinder. Using the formula for the cylinder’s volume, πr²h = 288π, and substituting r = 8 cm, we get:
    64πh = 288π → h = 288 / 64 = 4.5 cm.
    This question related to Chapter 12 Mathematics Class 10th NCERT. From the Chapter 12. Surface Areas and Volumes. Give answer according to your understanding.

    For more please visit here:
    https://www.tiwariacademy.in/ncert-solutions/class-10/maths/

    See less
    • 31