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A wire of length 20 cm is bent in different ways to form rectangles. For example, we can have a rectangle with length 7 cm and width 3 cm. We can also have one of length 5.5 cm and width 4.5 cm. (Think of a few more ways of forming such rectangles.) Can you write an expression for the area of such rectangles?

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If the length of the rectangle is x cm, then the width becomes 10 minus x cm because the total perimeter is 20 cm. Therefore, the area of the rectangle is x multiplied by 10 minus x.

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  1. The total length of the wire is 20 cm, so the perimeter of the rectangle is 20 cm. Since the perimeter formula is 2 multiplied by length plus width, the sum of length and width becomes 10 cm. If the length is x cm, then the width will be 10 minus x cm. The area of a rectangle is length multiplied by width. Therefore, the expression for the area of the rectangle is x multiplied by 10 minus x or 10x minus x square.

     

    For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 2 Introduction to Linear Polynomials (2026-27):

    https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-2/

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