Mayur Arya
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Who am I? b) I am a number less than 100. Two of my factors are 3 and 5. One of my digits is 1 more than the other.

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The number is 15. It is less than 100, divisible by both 3 and 5, and its digits 1 and 5 satisfy the condition where one digit (5) is 1 more than the other (4).

Class 6 Mathematics Chapter 5 Prime Time question answer

Class 6 NCERT Ganita Prakash Chapter 5 Prime Time

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  1. To solve, the number must be under 100, divisible by both 3 and 5, and its digits differ by 1. Numbers divisible by 3 and 5 have 15 as their least common multiple. Checking these, 15 fits perfectly, as its digits (1 and 5) meet the condition where one is exactly 1 more than the other. The factors of 15 include 1, 3, 5, and 15, further verifying it meets all the criteria.

    For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
    https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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