This is the acceleration experienced by a body due to Earth’s gravity.
Create multiple-choice questions (MCQs) for Chapter 7, “Gravitation,” from the NCERT Class 11 Physics textbook, as per the CBSE 2024–2025 syllabus. Cover key topics like the universal law of gravitation, gravitational force, acceleration due to gravity, variations with altitude and depth, orbital motion, escape velocity and Kepler’s laws. Ensure the MCQs are concise, conceptually clear and include four options with one correct answer. Focus on testing understanding, analytical skills and application of gravitational principles.
The acceleration due to gravity on Earth’s surface is approximately:
g₀ = 9.8 m/s²
This value represents the gravitational force experienced by an object per unit mass at the Earth’s surface. It is derived from the formula:
g₀ = G * M / R²
Where:
g₀ = acceleration due to gravity on Earth’s surface
G = gravitational constant (approximately 6.674 × 10^-11 N m²/kg²)
M = mass of the Earth (approximately 5.972 × 10^24 kg)
R = radius of the Earth (approximately 6,371 km or 6.371 × 10^6 m)
Substituting these values results in the standard value of g₀ ≈ 9.8 m/s².
This value can vary slightly depending on altitude, latitude, and local geological structures.
This question related to Chapter 7 physics Class 11th NCERT. From the Chapter 7. Gravitation. Give answer according to your understanding.
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