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Sonal Chauhan
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Asked: 2024-11-26T10:07:21+00:00 In:

What is the smallest number whose prime factorization includes two 3s, one 2, and one 7?

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The smallest number is 2 × 3² × 7 = 126. Multiplying these primes in increasing order ensures the smallest number containing exactly the specified prime factors.

Class 6 NCERT Ganita Prakash Chapter 5 Prime Time

class 6 Mathematics Textbook Chapter 5 question answer

 

and one 7class 6 maths | prime time | chapter 5 | part 2one 2prime time ncert textbook pdfsmallest number whose prime factorization includes two 3s
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    1. To construct the smallest number with the specified factors 2, 3², and 7, multiply them together:
      • 2 × 3² × 7 = 2 × 9 × 7 = 126.
      This number includes exactly one 2, two 3s, and one 7 in its prime factorization. No smaller number contains all these factors simultaneously, confirming 126 as the minimal valid solution for the problem.

      For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
      https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/

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