The smallest number is 2 × 3² × 7 = 126. Multiplying these primes in increasing order ensures the smallest number containing exactly the specified prime factors.
Class 6 NCERT Ganita Prakash Chapter 5 Prime Time
class 6 Mathematics Textbook Chapter 5 question answer
To construct the smallest number with the specified factors 2, 3², and 7, multiply them together:
• 2 × 3² × 7 = 2 × 9 × 7 = 126.
This number includes exactly one 2, two 3s, and one 7 in its prime factorization. No smaller number contains all these factors simultaneously, confirming 126 as the minimal valid solution for the problem.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/