The smallest 4-digit number divisible by 3, 5, and 7 is 1050. It is a multiple of their least common multiple (LCM = 105) and the smallest such number exceeding 1000.
class 6 Mathematics Textbook Chapter 5 question answer
class 6 Mathematics Chapter 5 Prime Time solutions
To find the smallest 4-digit number divisible by 3, 5, and 7, calculate their least common multiple (LCM):
• 3, 5, 7 are prime, so LCM = 3 × 5 × 7 = 105.
Divide the smallest 4-digit number, 1000, by 105: 1000 ÷ 105 = 9.52.
Round up to 10, multiply: 10 × 105 = 1050.
Thus, 1050 is the smallest 4-digit number divisible by 3, 5, and 7.
For more NCERT Solutions for Class 6 Math Chapter 5 Prime Time Extra Questions and Answer:
https://www.tiwariacademy.com/ncert-solutions-class-6-maths-ganita-prakash-chapter-5/