(ii) No for 100 and 1; yes for 10. The fourth side x satisfies 11 – (5 + 2) < x < 11 + 5 + 2, meaning 4 < x < 18. (iii) Each side must be strictly less ...
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In this sequence, the first term is 11 and common difference is -3. The explicit nth term simplifies to tn = 14 – 3n, while its recursive rule is stated as t1 = 11, tn = tn-1 – 3 for ...
Using Brahmagupta’s formula for a cyclic quadrilateral, with sides 5, 5, 12 and 12 units, the semiperimeter is 17 units. Therefore, area = √(12 × 12 × 5 × 5) = 60 square units.
No, a number ending in 0, 1, 4, 5, 6 or 9 is not always a square. While all square numbers do end with these digits, not every number with these digits is a square. For example, 26 ends in ...
The smallest 4-digit number divisible by 3, 5, and 7 is 1050. It is a multiple of their least common multiple (LCM = 105) and the smallest such number exceeding 1000. class 6 Mathematics Textbook Chapter 5 question answer class 6 Mathematics ...