The low value for Sc reflects the stability of Sc³⁺, which possesses a noble gas configuration, highlighting the preference for achieving noble gas stability in its oxidation states.
What is the significance of the low value for Sc in terms of its oxidation states, and how does it relate to the stability of Sc³⁺?
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The low value for scandium (Sc) in terms of third ionization enthalpy is significant in relation to its oxidation states, particularly the stability of Sc³⁺. Scandium readily forms Sc³⁺ due to its low third ionization enthalpy, allowing the removal of the third electron. The stability of Sc³⁺ is linked to the achievement of a noble gas configuration by losing three electrons. The low third ionization enthalpy of Sc facilitates the formation of Sc³⁺, emphasizing the significance of the electronic configuration in dictating the stability of oxidation states in transition metals like scandium.