Class 12 Physics
CBSE and UP Board
Atoms
Chapter-12 Exercise 12.3
NCERT Solutions for Class 12 Physics Chapter 12 Question-3
What is the shortest wavelength present in the Paschen series of spectral lines?
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Rydberg’s formula is given as:
hc /λ = 21.76 x 10⁻¹⁹ [1/n²₁ -1/n²₂]
Where,
h = Planck’s constant = 6.6 x 10⁻34 Js and c = Speed of light = 3 x 10⁸ m/s. (n₁ and n₂ are integers)
The shortest wavelength present in the Paschen series of the spectral lines is given for values n₁=3 and n₂=∝
hc /λ = 21.76 x 10⁻¹⁹ [1/(3)² -1/(∝) ²]
λ = (6.6 x 10⁻34 ) x (3 x 10⁸) x 9 ]/( 21.76 x 10⁻¹⁹)
= 8.189 x 10⁻⁷m = 818.9 nn