What is the moment of inertia of a thin ring of mass 𝑀 and radius 𝑅 about an axis passing through its center and perpendicular to its plane?
This question evaluates the formula for the moment of inertia of a thin ring.
Design multiple-choice questions (MCQs) for CBSE Class 11 Physics, Chapter 6: “System of Particles and Rotational Motion,” in accordance with the NCERT syllabus for the 2024-2025 academic year. The questions should comprehensively cover key topics such as the center of mass, torque, angular momentum, rotational kinematics, dynamics and equilibrium. Include a balanced mix of theoretical and numerical problems to assess students’ understanding of fundamental concepts as well as their ability to solve application-based problems. Ensure the questions vary in difficulty to cater to different levels of learners, from basic to advanced. Focus on clarity and precision in phrasing, making the questions engaging and easy to interpret. The goal is to provide effective practice material that helps students build a strong foundation in the chapter while also preparing them for examinations. Align the questions with NCERT standards to ensure relevance and consistency with the prescribed curriculum.
The moment of inertia of a thin ring about an axis passing through its center and perpendicular to its plane is given by 𝐼 = 𝑀𝑅² since all the mass is distributed at a distance 𝑅 from the axis.
This question related to Chapter 6 physics Class 11th NCERT. From the Chapter 6 System of Particles and Rotational Motion. Give answer according to your understanding.
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