From the work-energy theorem:
−F⋅ s = − 1/2mv²
Solving for the retarding force (F):
F= 21 ⋅ smv²/s
This gives the magnitude of the retarding force needed to stop the object over the displacement s.
What is the magnitude of the retarding force if the object stops after a displacement s?
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The magnitude of the retarding force F is given by F = mv²/2s , where m is the mass, v is the initial velocity, and s is the displacement over which the object stops.