What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

Current in the wire, I = 8 A

Magnitude of the uniform magnetic field, B = 0.15 T

Angle between the wire and magnetic field, 0 = 30°. Magnetic force per unit length on the wire is given as: f = BI sin0 = 0.15 x 8 x 1 x Sin30° = 0.6 N m¹

Hence, the magnetic force per unit length on the wire is 0.6 N m⁻¹.