We transform 105 into 100 + 5 and apply the identity with a = 100 and b = 5. Adding the squared values to the middle cross-product gives the correct total.
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We evaluate this square by rewriting 105 as the sum of 100 and 5. Applying our identity, we set a to 100 and b to 5. The square of 100 is 10000, and the square of 5 is 25. The cross-product term is calculated as two multiplied by 100 multiplied by 5, which gives 1000. Adding 10000, 1000, and 25 together gives 11025.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 4 Exploring Algebraic Identities (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-4/