Two point charges + 16 q and – 4 q are located at x = 0 and x = L The location of the point on x-axis at which resultant electric field due to these charges is zero is
The correct answer is:(c) 4L. The electric field due to a point charge is given by:E =kQ/r²
where k is Coulomb’s constant, Q is the charge, and r is the distance from the charge. Let the required point be at distance x from charge +16q (placed at x = 0). The charge −4q is at x = L.
For the net electric field to be zero, the field due to +16q must be equal and opposite to the field due to −4q:
Class 12th Science Physics NCERT MCQ Questions
NCERT Books MCQ Questions Session 2024-2025.
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The resultant electric field is zero where the fields due to +16q and -4q cancel each other. By using Coulomb’s law and setting the field magnitudes equal, solving for distance gives x = 4L from the charge +16q (toward the right). Answer: (c) 4L.
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