The perpendicular distances of the two chords from the centre are found using the Pythagoras Theorem. Since the chords lie on opposite sides of the centre, the required distance is the sum of these distances, which is seven centimetres.
Two parallel chords of lengths 6 cm and 8 cm are on opposite sides of the centre of a circle. If the radius of the circle is 5 cm, find the distance between the midpoints of the chords.
Share
Draw perpendiculars from the centre to both chords. These perpendiculars pass through the midpoints of the chords. Using the Pythagoras Theorem, the distances from the centre to the shorter and longer chords are found to be four centimetres and three centimetres, respectively. Since the chords are on opposite sides of the centre, the distance between their midpoints is seven centimetres.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/