The perpendicular distances of the two chords from the centre are found using the Pythagoras Theorem. Since the chords lie on opposite sides of the centre, the required distance is the sum of these distances, which is seven centimetres.
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The two right triangles have equal radii as hypotenuses and a common perpendicular side. Therefore, they are congruent by the RHS Congruence Criterion. Hence, the chord is divided into two equal parts.