There are 3 different rings to be worn in four fingers with at most one in each finger. Find the number of ways in which it can be done.
The study of Permutations and Combinations in Class 11th NCERT Maths (CBSE 2024-2025) unlocks the principles of counting and arrangement. This chapter covers factorial notation permutations combinations and their practical applications in solving real-world problems. It forms the basis for advanced topics like probability and statistics. The MCQ questions included help students evaluate their understanding and strengthen their analytical abilities. These questions are tailored to enhance logical reasoning and problem-solving skills preparing students for both board exams and competitive tests. By mastering this chapter students gain the confidence to tackle complex mathematical challenges and develop a deeper appreciation for the precision and logic of mathematics.
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Choice (b) is correct.
3 different rings to be worn in four fingers with at most one in each finger in P(4, 3) ways = 4!/(4 – 3)! = 4!/1! = 4 × 3 × 2 × 1/1 = 24
This question related to Chapter 5 maths Class 11th NCERT. From the Chapter 6: Permutations and Combinations. Give answer according to your understanding.
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