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The internal resistance of primary cell is 4 Ω. It generates a current of 0.2 A in an external resistance of 21 Ω. The rate at which chemical energy is consumed in providing the current is
Total resistance Rₜ = 21Ω + 4Ω = 25Ω. Using V = IR = 0.2 × 25 = 5V.
Power P = VI = 5 × 0.2 = 1W = 1 J/s.
Answer: (d) 1 J/s.
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