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The height of a cone is 30 cm. A small cone is cut off at the top at the top by a plane parallel to the base. If its volume be 1/27of the volume of the given cone, then the height above the base at which the section has been made, is
Master Class 10th Maths with NCERT solutions and MCQ-based questions from Chapter 12 Surface Areas and Volumes. Solve exercise questions short-answer problems and detailed explanations to understand concepts like surface areas and volumes of combinations of solids conversion of shapes and frustum of a cone. These resources align with the CBSE syllabus ensuring complete exam preparation. Regular practice will enhance your problem-solving skills and boost confidence for board exams. Access step-by-step solutions and revision notes tailored to simplify learning and help students excel. Focus on mastering formulas and their applications to strengthen your foundation. Begin practicing today to secure excellent results and achieve higher scores in exams.
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Given:
– Height of original cone = H = 30 cm,
– Volume of smaller cone = (1/27) × Volume of original cone.
For similar cones:
(h/H)³ = 1/27 ⇒ h/H = 1/3.
Height of smaller cone:
h = (1/3) × 30 = 10 cm.
Height above the base:
H – h = 30 – 10 = 20 cm.
Final Answer: c) 20 cm.
This question related to Chapter 12 Mathematics Class 10th NCERT. From the Chapter 12. Surface Areas and Volumes. Give answer according to your understanding.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions/class-10/maths/
Given:
– Height of original cone = H = 30 cm,
– Volume of smaller cone = (1/27) × Volume of original cone.
For similar cones:
(h/H)³ = 1/27 ⇒ h/H = 1/3.
Height of smaller cone:
h = (1/3) × 30 = 10 cm.
Height above the base:
H – h = 30 – 10 = 20 cm.
Final Answer: c) 20 cm.
For more please visit here:
https://www.tiwariacademy.in/ncert-solutions/class-10/maths/