Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure.
NCERT Maths Class 10 Chapter 14
Textbook Page No. 275
10th Maths Exercise 14.2
Question 3
The following data gives the distribution of total monthly household expenditure of 200 families of a village.
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It can be observed that the maximum class frequency is 40, belonging to 1500 – 2000 intervals.
Therefore, Modal class = 1500 – 2000
Lower limit (l) of modal class = 1500
Frequency (f₁) of modal class = 40
Frequency (f₀) of class preceding the modal class = 24
Frequency (f₂) of class succeeding the modal class 33
Class size (h) = 500
Mode = l + ((f₁ – f₀)/(2f₁ – f₀ – f₂)) × h = 500 + ((40 – 24)/(2 × 40 – 24 – 33)) × 500 = 1500 + 16/23 × 500 = 1500 + 347.826 = 1847.83
Therefore, modal monthly expenditure was ₹1847.83
To find the class mark, the following relation is used.
xᵢ = (Upper Limit + Lower Limit)/2
Class size (h) of the given data = 500.
Taking 2750 as assumed mean (a), dᵢ, uᵢ and fᵢuᵢ are calculated as follows.
From the table, we obtain
∑fᵢ = 200, ∑fᵢuᵢ = -35, a = 2750 and h = 500
mean (X̄) = a + (∑fᵢuᵢ / ∑fᵢ)h = 2750 + (-35/200) × 500 = 2750 – 87.5 = 2662.50