The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m ² is ₹ 4.

Here, d₁ = 45 cm and d₂ = 30 cm

∵ Area of one tile = 1/2d₁d₂=1/2x45x30=675cm²
∴ Area of 3000 tiles = 675 x 3000 = 2025000 cm²
= 2025000/10000 = 202.50 m2 [∵ 1m²=10000 cm²]
∵ Cost of polishing the floor per sq. meter = ₹ 4
∴ Cost of polishing the floor per 202.50 sq. meter = 4 x 202.50 = ₹ 810
Hence, the total cost of polishing the floor is ₹ 810.

Class 8 Maths Chapter 11 Exercise 11.2 Solution in Video

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