The perpendicular from the centre to the chord bisects it. Half the chord is 8 cm. Using the right triangle, radius² = 8² + 6² = 100. Therefore, radius = 10 cm.
The distance of a chord of length 16 cm from the centre of a circle is 6 cm. Find the radius of the circle.
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The chord is 16 cm long, so its half is 8 cm. The perpendicular distance from the centre to the chord is 6 cm. The perpendicular from the centre to a chord bisects the chord. Thus, we get a right triangle with sides 8 cm and 6 cm.
Radius² = 8² + 6²
= 64 + 36
= 100
Therefore, radius = 10 cm.
Hence, the radius of the circle is 10 cm.
For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):
https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/