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Ayushree
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Opposite angles of a cyclic quadrilateral are supplementary. (2x + 10) + (3x – 20) = 180 5x – 10 = 180 x = 38 Thus, ∠P = 86° and ∠R = 94°.

∠p = (2x + 10)°ganita manjari chapter 5 end of chapter exercises solutionsi’m up and down and round and round solved (2026-27)measures of ∠p and ∠rncert solutions – i’m up and down and round and round (new book 2026-27)pqrs is inscribed in a circle
Ayushree
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Let AB be a chord and O be the centre. Since OA = OB, O is equidistant from A and B. Therefore, O lies on the perpendicular bisector of AB. Hence proved.

ganita manjari chapter 5 end of chapter exercises solutionsi’m up and down and round and round solved (2026-27)ncert solutions – i’m up and down and round and round (new book 2026-27)perpendicular bisector of a chord passes through the centre