The diagonal of a quadrilateral shaped field is 24 m and the perpendiculars dropped on it from the remaining opposite vertices are 8 m and 13 m. Find the area of the field.

Here h₁ = 13 m, h₂ = 8 m and AC = 24 m
Area of quadrilateral ABCD
= Area of ∆ABC + Area of ∆ADC
= 1/2bxh₁+1/2bxh₂
= 1/2b(h₁+h₂)
= 1/2x24x(13+8)=1/2x24x21=252m²
Hence, required area of the field is 252 m².

Class 8 Maths Chapter 11 Exercise 11.2 Solution in Video

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