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Virat
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Asked: 2026-09-18T08:52:19+00:00 In:

The area of a right-angled triangle is 54 sq. cm. One of its legs has length 12 cm. Find its perimeter.

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Other leg is (2 x 54) / 12 = 9 cm. Hypotenuse is √(12² + 9²) = √(144 + 81) = √225 = 15 cm. Perimeter = 12 + 9 + 15 = 36 cm.

chapter 6 measuring space: perimeter and area question answerncert solutions – measuring space: perimeter and areaone of its legs has length 12 cmright-angled triangle is 54 sq
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    1. Area of a right-angled triangle = (1/2) x leg1 x leg2.

      Given Area = 54 sq. cm and leg1 = 12 cm:

      54 = (1/2) x 12 x leg2 = 6 x leg2

      leg2 = 54 / 6 = 9 cm.

      By Baudhāyana-Pythagoras theorem, hypotenuse = √(leg1² + leg2²):

      hypotenuse = √(12² + 9²) = √(144 + 81) = √225 = 15 cm.

      Perimeter = leg1 + leg2 + hypotenuse = 12 + 9 + 15 = 36 cm.

       

      For more NCERT Solutions of Class 9 Ganita Manjari Chapter 6 Measuring Space: Perimeter and Area Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-6/

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