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Asked: 2026-10-03T06:01:03+00:00 In:

Suppose P is a point on side AB of △ABC and the line through P parallel to BC meets AC in point Q. For parts (i) to (iii), assume AP = 1, AQ = √5 and see Fig. 12.39. (i) If PB = 2 find QC. (Hint: See the dotted line) (ii) If PB = 1/3 find QC. (Hint: See the dotted lines) (iii) If PB = 2/3 find QC. (Hint: Divide both PB and AP suitably.) (iv) Show that if AP/PB is a rational number, then AP/PB = AQ/QC. In Grade 10, you will prove this equality without assuming AP/PB is rational. That will require a new idea.

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(i) QC = 2√5. (ii) QC = √5/3. (iii) QC = 2√5/3. (iv) Dividing AP and PB into equal units and drawing parallels produces congruent intercepts on AC, yielding AP/PB = m/n = AQ/QC.

Class 9 maths ganita manjari part 2 chapter 12 question answer
Class 9 Ganita Manjari Part 2 chapter 12 Quadrilaterals solutions

ab of △abc and the line through p parallel to bccbse class 9 maths ganita manjari part 2 solutionsclass 9 maths ganita manjari part 2 chapter 12 question answerganita manjari part 2 chapter 12 quadrilaterals solutionsshow that if ap/pb is a rational numberyou will prove this equality without assuming
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    1. (i) Bisecting PB creates 2 segments equal to AP, intercepting 2 segments of length √5 along QC, so QC = 2√5. (ii) Trisecting AP gives three 1/3-length intervals matching PB, so QC = √5/3. (iii) Using 1/3-sized units gives AP:PB = 3:2, making QC = 2/3 AQ = 2√5/3. (iv) Let AP/PB = m/n. Partitioning AB into equal segments and drawing parallels intercepts equal subsegments on AC, proving AP/PB = AQ/QC.

       

      For more NCERT Solutions of Class 9 Maths Ganita Manjari Part 2 Chapter 12 Quadrilaterals Question Answer (2026-27)

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-12/

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