(i) Exactly 3 distinct cyclic edge orderings can be formed. (ii) If the 4 points form a convex hull: 1 is convex and 2 are self-intersecting. If 1 point is inside: 0 are convex, 3 are non-convex and 0 self-intersect.
Class 9 Ganita Manjari part 2 Chapter 12 Solutions
Class 9 Ganita Manjari Part 2 Chapter 12 Page 78 Question Answer
(i) The 4 points can be arranged cyclically in (4-1)!/2 = 3 distinct edge-connectivity cycles, giving 3 quadrilaterals. (ii) There are two cases: • Case 1 (points form a convex quadrilateral): Exactly 1 is convex and the other 2 are self-intersecting. • Case 2 (one point lies inside the triangle of the other three): None are convex; all 3 form non-convex dart shapes.
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