Satellite is revolving around earth. If its height is increased to four times the height of geostationary satellite, what will become its time period?

According to Kepler’s law of periods, the ratio of the orbital periods of two planets is related to the ratio of their semi-major axes. Specifically, the ratio of the periods (T₂/T₁) equals the ratio of their radii raised to the power of three-halves. In this case, if the radius of the second planet is four times that of the first, the calculation shows that T₂/T₁ equals eight.
Therefore, if the orbital period of the first planet is 1 day, the orbital period of the second planet would be 8 days, demonstrating the significant impact of radius on orbital time.

According to Kepler’s law of periods,
T₂/T₁ = (r₂/r₁)³/² = (4/1)³/² = 8
T₂ = 8T₁= 8 x 1 day = 8 days