Virat
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Rakvi performed an activity by taking ethanoic acid and sodium hydrogen carbonate as shown in the diagram given below. The diagram shows an experimental setup where ethanol is oxidised to ethanoic acid using an oxidizing agent, producing CO2 gas sodium bicarbonate (NaHCO3) may be used to test the acidic nature of the product. Answer the following questions based on the given information: (i) What is the observable change when CO2 gas reacts with lime water in the in this experiment? (ii) Rakvi observed that a salt X is formed with the evolution of gas Y. Identify the salt X and evolved gas Y. (iii) Write the chemical equation of the reaction involved.

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Lime water turns milky because carbon dioxide gas reacts with calcium hydroxide solution to form calcium carbonate. When ethanoic acid reacts with sodium hydrogen carbonate, the products formed are sodium ethanoate (X), water, and carbon dioxide gas (Y).

cbse class 10 science half yearly sample papers

sample paper for class 10 science board exam 2026

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  1. (a) Lime water turns milky because carbon dioxide gas reacts with calcium hydroxide solution to form calcium carbonate. Calcium carbonate is insoluble in water and appears as a white precipitate, giving the solution a milky appearance. This reaction is a common laboratory test for the presence of carbon dioxide gas.

     

    (b) When ethanoic acid reacts with sodium hydrogen carbonate, the products formed are sodium ethanoate (X), water, and carbon dioxide gas (Y). The reaction demonstrates the typical acid–carbonate reaction, producing effervescence due to carbon dioxide release. The sodium salt formed is soluble, while the gas evolved can turn lime water milky.

    (c) Carbon dioxide released from the reaction is confirmed using lime water. It reacts with calcium hydroxide to form insoluble calcium carbonate, which makes the solution appear milky. The balanced reaction is:

    Ca(OH)₂ + CO₂ → CaCO₃ + H₂O. This simple test is widely used to detect carbon dioxide gas.

     

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