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Ayushree
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Asked: 2026-08-04T04:06:25+00:00 In:

Quadrilateral PQRS is inscribed in a circle. If ∠P = (2x + 10)° and ∠R = (3x – 20)°, find the value of x and the measures of ∠P and ∠R.

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Opposite angles of a cyclic quadrilateral are supplementary.

(2x + 10) + (3x – 20) = 180

5x – 10 = 180

x = 38

Thus, ∠P = 86° and ∠R = 94°.

∠p = (2x + 10)°ganita manjari chapter 5 end of chapter exercises solutionsi’m up and down and round and round solved (2026-27)measures of ∠p and ∠rncert solutions – i’m up and down and round and round (new book 2026-27)pqrs is inscribed in a circle
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    1. PQRS is a cyclic quadrilateral, so its opposite angles P and R are supplementary.

      Therefore,

      (2x + 10) + (3x – 20) = 180

      5x – 10 = 180

      5x = 190

      x = 38

      Now,

      ∠P = 2(38) + 10 = 86°

      ∠R = 3(38) – 20 = 94°

      Hence, x = 38, ∠P = 86° and ∠R = 94°.

       

      For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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