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Ayushree
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Asked: 2026-08-04T04:06:15+00:00 In:

Prove that the perpendicular bisector of a chord passes through the centre of the circle.

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Let AB be a chord and O be the centre. Since OA = OB, O is equidistant from A and B. Therefore, O lies on the perpendicular bisector of AB. Hence proved.

ganita manjari chapter 5 end of chapter exercises solutionsi’m up and down and round and round solved (2026-27)ncert solutions – i’m up and down and round and round (new book 2026-27)perpendicular bisector of a chord passes through the centre
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    1. Let AB be a chord of a circle with centre O. Join OA and OB. Since OA and OB are radii of the same circle, OA = OB. Thus, O is equidistant from the two endpoints A and B of the chord. The locus of points equidistant from A and B is the perpendicular bisector of AB. Therefore, the perpendicular bisector of chord AB passes through the centre O of the circle. Hence proved.

       

      For more NCERT Solutions for Class 9 Maths Ganita Manjari Chapter 5 I’m Up and Down and Round and Round (2026-27):

      https://www.tiwariacademy.com/ncert-solutions/class-9/maths/ganita-manjari-chapter-5/

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