PQR is a triangle, right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Given: PQ = 10 cm, PR = 24 cm
Let QR be x cm.
In right angled triangle QPR,
(Hypotenuse)² = (Base)² + (Perpendicular)² [By Pythagoras theorem]
⇒ (QR)² = (PQ)² + (PR)²
⇒ x² = (10)² + (24)²
⇒ x² = 100 + 576 = 676
⇒ x = √676 = 26 cm
Thus, the length of QR is 26 cm.

Class 7 Maths Chapter 6 Exercise 6.5

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