One mole of an ideal gas at STP occupies 22.4 L. What is the ratio of molar volume to atomic volume of a mole of hydrogen? Why is the ratio so large. Take radius of hydrogen molecule to be 1ºA.

1 A⁰ = 10⁻ ¹⁰ m
Atomic volume of 1 mole of hydrogen
= Avagadros number × volume of hydrogen molecule
= 6.023 × 10²³ × π× (10⁻¹⁰ m)³
= 25.2 × 10⁻⁷ m³
Molar volume = 22.4 L = 22.4 × 10⁻³ m³
Molar volume / Atomic volume = 22.4×10⁻³/25.2×10⁷ = 0.89 × 104 ≈ 104
This ratio is large because actual size of gas molecule is negligible in
comparison to the inter molecular separation.