Given, p||q and cut by a transversal line.
∵ 125° + e = 180° [Linear pair]
∴ e = 180° – 125° = 55° ……….(i)
Now e = f = 55° [Vertically opposite angles]
Also a = f = 55° [Alternate interior angles]
a = b + 180° [Linear pair]
⇒ 55° + b = 180° [From equation (i)]
⇒ b = 180° – 55° = 125°
Now a = c = 55° and b = d = 125° [Vertically opposite angles]
Thus, a = 55°,b = 125°, c = 55°, d = 125°, e = 55° and f = 55°.

Class 7 Maths Chapter 5 Exercise 5.2

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