2 jahnvi87 Asked: March 23, 20232023-03-23T03:59:51+00:00 2023-03-23T03:59:51+00:00In: Class 9 Maths In Fig. 6.17, POQ is a line. Ray OR is perpendicular to line PQ. OS is another ray lying between rays OP and OR. 2 Prove that ∠ ROS = 1/2 (∠ QOS – ∠ POS). Class 9 Ncert math’s chapter 6 Lines and Angles Page No. 97 Exercise 6.1 Question 5 chapter 6class 9ncert maths Share Facebook 1 Answer Voted Oldest Recent Best Answer lalit898 2023-03-23T11:37:20+00:00Added an answer on March 23, 2023 at 11:37 am RHS = 1/2 (∠QOS – ∠POS) = 1/2 [(∠QOP + ∠ROS) – (∠POR – ∠ROS)] [∵ ∠QOS = ∠QOR + ∠ROS and ∠POS = ∠POR – ∠ROS] = 1/2 [∠QOR + ∠ROS – ∠POR + ∠ROS] = 1/2 [90° + ∠ROS – 90° + ∠ROS] [∵ ∠QOR = 90° and ∠POR = 90°] = 1/2 [2∠ROS] = ∠ROS = LHS 2 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.
RHS = 1/2 (∠QOS – ∠POS)
= 1/2 [(∠QOP + ∠ROS) – (∠POR – ∠ROS)]
[∵ ∠QOS = ∠QOR + ∠ROS and ∠POS = ∠POR – ∠ROS]
= 1/2 [∠QOR + ∠ROS – ∠POR + ∠ROS]
= 1/2 [90° + ∠ROS – 90° + ∠ROS] [∵ ∠QOR = 90° and ∠POR = 90°]
= 1/2 [2∠ROS]
= ∠ROS = LHS