I am looking for a video solution and a PDF of NCERT math chapter 6 exercise 6.1 for class 9. I want to understand how to solve the problems related to lines and angles. Can you please provide video solution having clear explanation and examples?
NCERT Class 9 mathematics chapter 6
Page No. 97
Exercise 6.1
Question No. 2
Given: Lines XY and MN intersects at O,
∠POY = 90° and a:b = 2:3
Let, a = 2x, therefore b = 3x
Here, ∠XOM + ∠POM + ∠POY = 180° [∵ XOY is a straight line]
⇒ 3x + 2x + 90° = 180° [∵ ∠POY = 90°]
⇒ 5x + 90° = 180°
⇒ 5x = 180° – 90° = 90°
⇒ x = 180°/5 = 18°
Hence, ∠XOM = 3x = 3 × 18° = 54° and
∠POM = 2x = 2 × 18° = 36°
Here, ∠XON = ∠MOY
⇒ c = ∠POM + ∠POY [∵ Vertically Opposite Angles]
⇒ c = 36° + 90° = 126° [∵ ∠XON = c and ∠MOY = ∠POM + ∠POY ]