In Exercises 7.3 and 7.4, what is the net power absorbed by each circuit over a complete cycle. Explain your answer.

In the inductive circuit,

rms value of current, I = 15.92 A

rms value of voltage, V = 220 V

Hence, the net power absorbed can be obtained by the relation,

P = VI cos φ

Where, φ = Phase difference between V and I.

For a pure inductive circuit, the phase difference between alternating voltage and current is 90° i.e., φ= 90°.

Hence, P = 0 i.e., the net power is zero.

In the capacitive circuit, rms value of current, I = 2.49 A, rms value of voltage, V = 110 V Hence, the net power absorbed can be obtained as:

P = VI Cos φ

For a pure capacitive circuit, the phase difference between alternating voltage and current is 90° i.e.,

φ = 90°.

Hence, P = 0 i.e., the net power is zero.