In angle PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.

Given that: in APQR, angle Q is right angled.
Let QR x, therefore, PR = 25-x
In △PQR, by Pythagoras theorem, we have
PR² = PQ²+OQ²
⇒ (25-x)² = (5)²+(x)²
⇒ 625+x²-50x = 25+x²
⇒ 625-50x = 25
⇒ 50x = 600
⇒ x = 12
⇒ QR = 12
Therefore, PR = 25-12 = 13
Now, sin P = QR/PR = 12/13, cos P = PQ/PR = 5/13 and tan P = QR/PQ = 12/5

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