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Jay Singh
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Asked: 2020-10-30T03:31:03+00:00 In:

In angle PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.

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NCERT Solutions for Class 10 Maths Chapter 8
Important NCERT Questions
Introduction Trigonometry
NCERT Books for Session 2022-2023
CBSE Board and UP Board Others state Board
EXERCISE 8.1
Page No:181
Questions No:10

2020-2021cbsechapter 8class10introduction trigonometrymathematicsncert
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    1. Best Answer
      In angle PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.

      Given that: in APQR, angle Q is right angled.
      Let QR x, therefore, PR = 25-x
      In △PQR, by Pythagoras theorem, we have
      PR² = PQ²+OQ²
      ⇒ (25-x)² = (5)²+(x)²
      ⇒ 625+x²-50x = 25+x²
      ⇒ 625-50x = 25
      ⇒ 50x = 600
      ⇒ x = 12
      ⇒ QR = 12
      Therefore, PR = 25-12 = 13
      Now, sin P = QR/PR = 12/13, cos P = PQ/PR = 5/13 and tan P = QR/PQ = 12/5

      Here is the video explanation of the question😺👇

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    2. Get Hindi Medium and English Medium NCERT Solution for Class 10 Maths to download.
      Please follow the link to visit website for first and second term exams solutions.
      https://www.tiwariacademy.com/ncert-solutions/class-10/maths/chapter-8/

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