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In an experiment to measure the resistance of a cell by a potentiometer, it is found that the balance point is a length 2 m, when the cell is shunted by a 5 Ω resistance and at a length of 3 m, when the cell is shunted by a 10 Ω resistance. The internal resistance of the cell is then
Let the internal resistance be r and the balance lengths be
I₁ = 2m, l₂ = 3m.
Using the potentiometer equation:
l₁/l₂ = R₁/R₂
Solving for r, we get 1 Ω. Answer: (a) 1 Ω.
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